y^'=2x-y,y(0)=1

Lösung

y^{^{'}} = 2 x - y, y (0) = 1

y = 2 (x - 1) + \frac{3}{e ^{x}}

Schritte zur Lösung

y^{'} (x) = 2 x - y

Solve linear ODE:

y = 2 (x - 1) + \frac{3}{e ^{x}}

y = 2 (x - 1) + \frac{3}{e ^{x}}

y^{^{'}} = x^{9} + 1

\frac{\partial}{\partial x} (\frac{( 2 + t ^{2} )}{3 x - x ^{3}})

d er i v a t i v e y = e^{2 - x}

\int_{0}^{3} (9 - x^{2}) d x

\frac{d}{d a} (\frac{tan ^{2} ( a ) - sin ^{2} ( a )}{tan ^{2} ( a )})