y^'-e^xe^y=-1

Lösung

y^{^{'}} - e^{x} e^{y} = - 1

y = - ln (- x - c_{1}) - x

Schritte zur Lösung

y^{'} (x) - e^{x} e^{y} = - 1

Solve using substitution:

y = - ln (- x - c_{1}) - x

y = - ln (- x - c_{1}) - x

\frac{\partial}{\partial x} (e^{1 + x^{2} - y^{2}})

\frac{d}{d x} (6 cos (2 x) - e^{- x})

t an g e n t f (x) = 2 x^{3} + 7 x^{2} - 8 x - 3, at x = - 1

x \to 1 - lim (1 - x - [x] - [1 - x])

x \to 4 - lim (\frac{1}{( x - 4 ) ^{2}})