What is the limit as x approaches-8-of x^2+2/(x+8) ?

The limit as x approaches-8-of x^2+2/(x+8) is -infinity

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limit as x approaches-8-of x^2+2/(x+8)

x \to - 8 - lim (x^{2} + \frac{2}{x + 8})

- \infty

Solution steps

x \to - 8 - lim (x^{2} + \frac{2}{x + 8})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to - 8 - lim (x^{2}) + x \to - 8 - lim (\frac{2}{x + 8})

x \to - 8 - lim (x^{2}) = 64

x \to - 8 - lim (\frac{2}{x + 8}) = - \infty

= 64 - \infty

Apply Infinity Property:

c - \infty = - \infty

= - \infty

What is the limit as x approaches-8-of x^2+2/(x+8) ?
The limit as x approaches-8-of x^2+2/(x+8) is -infinity