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tangent f(x)=-8x^2-7x,\at x=-4

解答

切线

f (x) = - 8 x^{2} - 7 x, at x = - 4

解答

y = 57 x + 128

求解步骤

找到切点:

(- 4, - 100)

计算

f (x) = - 8 x^{2} - 7 x

的斜率:

\frac{df ( x )}{d x} = - 16 x - 7

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 57

找到斜率 m=

57

且穿过

(- 4, - 100)

的直线:

y = 57 x + 128

y = 57 x + 128

作图

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