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tangent f(x)=((x+1)/(x-1))^3,\at x=2

解答

切线

f (x) = (\frac{x + 1}{x - 1})^{3}, at x = 2

解答

y = - 54 x + 135

求解步骤

找到切点:

(2, 27)

计算

f (x) = (\frac{x + 1}{x - 1})^{3}

的斜率:

\frac{df ( x )}{d x} = - \frac{6 ( x + 1 ) ^{2}}{( x - 1 ) ^{4}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 54

找到斜率 m=

- 54

且穿过

(2, 27)

的直线:

y = - 54 x + 135

y = - 54 x + 135

作图

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