What is the tangent of f(x)=((x+1)/(x-1))^3,\at x=2 ?

The tangent of f(x)=((x+1)/(x-1))^3,\at x=2 is y=-54x+135

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=((x+1)/(x-1))^3,\at x=2

tangent of

f (x) = (\frac{x + 1}{x - 1})^{3}, at x = 2

y = - 54 x + 135

Solution steps

Find the tangent point:

(2, 27)

Find the slope of

f (x) = (\frac{x + 1}{x - 1})^{3} : \frac{df ( x )}{d x} = - \frac{6 ( x + 1 ) ^{2}}{( x - 1 ) ^{4}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 54

Find the line with slope m=

- 54

and passing through

(2, 27) : y = - 54 x + 135

y = - 54 x + 135

What is the tangent of f(x)=((x+1)/(x-1))^3,\at x=2 ?
The tangent of f(x)=((x+1)/(x-1))^3,\at x=2 is y=-54x+135