What is the tangent of f(x)=9x^2-x^3,(2,28) ?

The tangent of f(x)=9x^2-x^3,(2,28) is y=24x-20

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tangent of f(x)=9x^2-x^3,(2,28)

tangent of

f (x) = 9 x^{2} - x^{3}, (2, 28)

y = 24 x - 20

Solution steps

Find the slope of

f (x) = 9 x^{2} - x^{3} : \frac{df ( x )}{d x} = 18 x - 3 x^{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 24

Find the line with slope m=

24

and passing through

(2, 28) : y = 24 x - 20

y = 24 x - 20

What is the tangent of f(x)=9x^2-x^3,(2,28) ?
The tangent of f(x)=9x^2-x^3,(2,28) is y=24x-20