y^'-(2y)/x =-x^2y^2

Lösung

y^{^{'}} - \frac{2 y}{x} = - x^{2} y^{2}

y = \frac{5 x ^{2}}{x ^{5} + c _{1}}

Schritte zur Lösung

y^{'} (x) - \frac{2 y}{x} = - x^{2} y^{2}

Solve Bernoulli ODE:

y = \frac{5 x ^{2}}{x ^{5} + c _{1}}

y = \frac{5 x ^{2}}{x ^{5} + c _{1}}

\int \frac{a x}{x ^{4} + b ^{4}} d x

x \to 0 lim (\frac{- 1}{5 x})

f (x) = sec^{2} (2 x)

x \to - 2 lim (2 x + 2 + x)

\frac{\partial}{\partial x} (e^{x y z^{7}})