derivative of ln(x^2-2x+1)

Lösung

\frac{d}{d x} (ln (x^{2} - 2 x + 1))

\frac{2}{x - 1}

Schritte zur Lösung

\frac{d}{d x} (ln (x^{2} - 2 x + 1))

Wende die Kettenregel an:

\frac{1}{x ^{2} - 2 x + 1} \frac{d}{d x} (x^{2} - 2 x + 1)

= \frac{1}{x ^{2} - 2 x + 1} \frac{d}{d x} (x^{2} - 2 x + 1)

\frac{d}{d x} (x^{2} - 2 x + 1) = 2 x - 2

= \frac{1}{x ^{2} - 2 x + 1} (2 x - 2)

Vereinfache

\frac{1}{x ^{2} - 2 x + 1} (2 x - 2) : \frac{2}{x - 1}

= \frac{2}{x - 1}

x \to - 19 lim (13 + x)

\int \frac{x ^{2}}{25 - x ^{2}} d x

\frac{d}{d x} (x^{y} + y^{x})

t an g e n t f (x) = x^{3} - 3 x + 2, at x = 3

n = 1 \sum \infty 7 (\frac{1}{10})^{n}