(dy)/(dt)=4-(1.5y)/(10+2.5t)

Lösung

\frac{d y}{d t} = 4 - \frac{1.5 y}{10 + 2.5 t}

y = 10 + 2.5 t + \frac{c _{1}}{( 10 + 2.5 t ) ^{0.6}}

Schritte zur Lösung

\frac{d y}{d t} = 4 - \frac{1.5 y}{10 + 2.5 t}

Solve linear ODE:

y = 10 + 2.5 t + \frac{c _{1}}{( 10 + 2.5 t ) ^{0.6}}

y = 10 + 2.5 t + \frac{c _{1}}{( 10 + 2.5 t ) ^{0.6}}

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