y^'-2y=y^3

Lösung

y^{^{'}} - 2 y = y^{3}

y = \frac{2}{e ^{- 4 t - c_{1}} - 1}, y = - \frac{2}{e ^{- 4 t - c_{1}} - 1}

Schritte zur Lösung

y^{'} (t) - 2 y = y^{3}

Solve Bernoulli ODE:

y = \frac{2}{e ^{- 4 t - c_{1}} - 1}, y = - \frac{2}{e ^{- 4 t - c_{1}} - 1}

y = \frac{2}{e ^{- 4 t - c_{1}} - 1}, y = - \frac{2}{e ^{- 4 t - c_{1}} - 1}

\frac{d}{d x} (arccsc (tan (e^{x})))

\frac{\partial}{\partial x} (e^{2 x} cos (8 y))

(\frac{1}{x ( ln ( x ) ) ^{2}})^{^{'}}

\frac{\partial}{\partial x} (\frac{x ^{2}}{2})

\frac{d}{d x} ((x + 1)^{3})