What is the tangent of f(x)=x(x^2-4x+5)^4,\at x=2 ?

The tangent of f(x)=x(x^2-4x+5)^4,\at x=2 is y=x

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tangent of f(x)=x(x^2-4x+5)^4,\at x=2

tangent of

f (x) = x (x^{2} - 4 x + 5)^{4}, at x = 2

y = x

Solution steps

Find the tangent point:

(2, 2)

Find the slope of

f (x) = x (x^{2} - 4 x + 5)^{4} : \frac{df ( x )}{d x} = (x^{2} - 4 x + 5)^{4} + 4 x (x^{2} - 4 x + 5)^{3} (2 x - 4)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(2, 2) : y = x

y = x

What is the tangent of f(x)=x(x^2-4x+5)^4,\at x=2 ?
The tangent of f(x)=x(x^2-4x+5)^4,\at x=2 is y=x