What is the solution for y^'=arctan(x/2) ?

The solution for y^'=arctan(x/2) is y=xarctan(x/2)-ln(x^2+4)+c_{1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^'=arctan(x/2)

y^{^{'}} = arctan (\frac{x}{2})

y = x arctan (\frac{x}{2}) - ln (x^{2} + 4) + c_{1}

Solution steps

y^{'} (x) = arctan (\frac{x}{2})

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int arctan (\frac{x}{2}) d x

\int arctan (\frac{x}{2}) d x = x arctan (\frac{x}{2}) - ln (x^{2} + 4) + c_{1}

y = x arctan (\frac{x}{2}) - ln (x^{2} + 4) + c_{1}

What is the solution for y^'=arctan(x/2) ?
The solution for y^'=arctan(x/2) is y=xarctan(x/2)-ln(x^2+4)+c_{1}