What is the solution for y^'=([xy^2+(y)e^x])/(e^x) ?

The solution for y^'=([xy^2+(y)e^x])/(e^x) is y=(2e^x)/(-x^2+c_{1)}

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y^'=([xy^2+(y)e^x])/(e^x)

y^{^{'}} = \frac{[ x y ^{2} + ( y ) e ^{x} ]}{e ^{x}}

y = \frac{2 e ^{x}}{- x ^{2} + c _{1}}

Solution steps

y^{'} (x) = \frac{[ x y ^{2} + ( y ) e ^{x} ]}{e ^{x}}

Solve Bernoulli ODE:

y = \frac{2 e ^{x}}{- x ^{2} + c _{1}}

y = \frac{2 e ^{x}}{- x ^{2} + c _{1}}

What is the solution for y^'=([xy^2+(y)e^x])/(e^x) ?
The solution for y^'=([xy^2+(y)e^x])/(e^x) is y=(2e^x)/(-x^2+c_{1)}