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Popular Calculus >

y^'=2x,y(1)=7

Solution

y^{^{'}} = 2 x, y (1) = 7

Solution

y = x^{2} + 6

Solution steps

y^{'} (x) = 2 x

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 2 x d x

\int 2 x d x = x^{2} + c_{1}

y = x^{2} + c_{1}

Apply initial conditions:

y = x^{2} + 6

y = x^{2} + 6

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=2x,y(1)=7 ?
The solution for y^'=2x,y(1)=7 is y=x^2+6