What is the derivative of (5x/(sqrt(x^2+7))) ?

The derivative of (5x/(sqrt(x^2+7))) is (35)/((x^2+7)sqrt(x^2+7))

What is the first derivative of (5x/(sqrt(x^2+7))) ?

The first derivative of (5x/(sqrt(x^2+7))) is (35)/((x^2+7)sqrt(x^2+7))

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\frac{d}{d x} (\frac{5 x}{x ^{2} + 7})

\frac{35}{( x ^{2} + 7 ) x ^{2} + 7}

Solution steps

\frac{d}{d x} (\frac{5 x}{x ^{2} + 7})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{x}{x ^{2} + 7})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 5 \cdot \frac{\frac{d x}{d x} x ^{2} + 7 - \frac{d}{d x} ( x ^{2} + 7 ) x}{( x ^{2} + 7 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 7) = \frac{x}{x ^{2} + 7}

= 5 \cdot \frac{1 \cdot x ^{2} + 7 - \frac{x}{x ^{2} + 7} x}{( x ^{2} + 7 ) ^{2}}

Simplify

5 \cdot \frac{1 \cdot x ^{2} + 7 - \frac{x}{x ^{2} + 7} x}{( x ^{2} + 7 ) ^{2}} : \frac{35}{( x ^{2} + 7 ) x ^{2} + 7}

= \frac{35}{( x ^{2} + 7 ) x ^{2} + 7}

What is the derivative of (5x/(sqrt(x^2+7))) ?
The derivative of (5x/(sqrt(x^2+7))) is (35)/((x^2+7)sqrt(x^2+7))
What is the first derivative of (5x/(sqrt(x^2+7))) ?
The first derivative of (5x/(sqrt(x^2+7))) is (35)/((x^2+7)sqrt(x^2+7))