(\partial)/(\partial x)(sqrt(20-4x^2-3y^2))

Lösung

\frac{\partial}{\partial x} (20 - 4 x^{2} - 3 y^{2})

- \frac{4 x}{20 - 4 x ^{2} - 3 y ^{2}}

Schritte zur Lösung

\frac{\partial}{\partial x} (20 - 4 x^{2} - 3 y^{2})

Behandle

y

als Konstante

Wende die Kettenregel an:

\frac{1}{2 20 - 4 x ^{2} - 3 y ^{2}} \frac{\partial}{\partial x} (20 - 4 x^{2} - 3 y^{2})

= \frac{1}{2 20 - 4 x ^{2} - 3 y ^{2}} \frac{\partial}{\partial x} (20 - 4 x^{2} - 3 y^{2})

\frac{\partial}{\partial x} (20 - 4 x^{2} - 3 y^{2}) = - 8 x

= \frac{1}{2 20 - 4 x ^{2} - 3 y ^{2}} (- 8 x)

Vereinfache

\frac{1}{2 20 - 4 x ^{2} - 3 y ^{2}} (- 8 x) : - \frac{4 x}{20 - 4 x ^{2} - 3 y ^{2}}

= - \frac{4 x}{20 - 4 x ^{2} - 3 y ^{2}}

\int 29 x^{2} ln (x) d x

ma c l a u r in \frac{1}{3 2 x + 1}

\frac{d ^{2}}{d x ^{2}} (e^{5 x})

\frac{\partial}{\partial x} (10 x y)

d er i v a t i v e y = 2 x^{2} e^{x} + 4 x^{3}