What is area 4-(x-2)^2,5-(x-4)^2,2,4 ?

The answer to area 4-(x-2)^2,5-(x-4)^2,2,4 is 17/4

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area 4-(x-2)^2,5-(x-4)^2,2,4

area

4 - (x - 2)^{2}, 5 - (x - 4)^{2}, 2, 4

\frac{17}{4}

Decimal

4.25

Solution steps

Apply the area formula:

\int_{2}^{4} 4 - (x - 2)^{2} - (5 - (x - 4)^{2}) d x

Solve

\int_{2}^{4} 4 - (x - 2)^{2} - (5 - (x - 4)^{2}) d x : \frac{17}{4}

The area is:

= \frac{17}{4}

What is area 4-(x-2)^2,5-(x-4)^2,2,4 ?
The answer to area 4-(x-2)^2,5-(x-4)^2,2,4 is 17/4