extreme (x^2-7x+26)/(x-5)

Lösung

extrempunkte

\frac{x ^{2} - 7 x + 26}{x - 5}

Maximum (1, - 5), Minimum (9, 11)

Schritte zur Lösung

f^{'} (x) = \frac{x ^{2} - 10 x + 9}{( x - 5 ) ^{2}}

Intervalle finden:

Ansteigend

: - \infty < x < 1,

Absteigend

: 1 < x < 5,

Absteigend

: 5 < x < 9,

Ansteigend

: 9 < x < \infty

Stecke

x = 1

\frac{x ^{2} - 7 x + 26}{x - 5} : - 5

Maximum (1, - 5)

Stecke

x = 9

\frac{x ^{2} - 7 x + 26}{x - 5} : 11

Minimum (9, 11)

Maximum (1, - 5), Minimum (9, 11)

e x t re m e f (x) = 3 x^{3} e^{- x}, - 1 \leq x \leq 5

e x t re m e (x + 8)^{\frac{2}{3}}

e x t re m e f (x) = x^{2} - y^{2} - 7 x - 4 y

e x t re m e f (x, y) = x^{3} + y^{3} - 21 x y

e x t re m e f (x) = 2 x^{3} + 3 x^{2} - 36 x + 1