extreme 30x^3-19x^2-14x+8

Lösung

extrempunkte

30 x^{3} - 19 x^{2} - 14 x + 8

Maximum (\frac{19 - 1621}{90}, \frac{1621 1621 - 42769}{12150} + 8), Minimum (\frac{19 + 1621}{90}, \frac{- 42769 - 1621 1621}{12150} + 8)

Schritte zur Lösung

f^{'} (x) = 90 x^{2} - 38 x - 14

Intervalle finden:

Ansteigend

: - \infty < x < \frac{- 1621 + 19}{90},

Absteigend

: \frac{- 1621 + 19}{90} < x < \frac{1621 + 19}{90},

Ansteigend

: \frac{1621 + 19}{90} < x < \infty

Stecke

x = \frac{19 - 1621}{90}

30 x^{3} - 19 x^{2} - 14 x + 8 : \frac{1621 1621 - 42769}{12150} + 8

Maximum (\frac{19 - 1621}{90}, \frac{1621 1621 - 42769}{12150} + 8)

Stecke

x = \frac{19 + 1621}{90}

30 x^{3} - 19 x^{2} - 14 x + 8 : \frac{- 42769 - 1621 1621}{12150} + 8

Minimum (\frac{19 + 1621}{90}, \frac{- 42769 - 1621 1621}{12150} + 8)

Maximum (\frac{19 - 1621}{90}, \frac{1621 1621 - 42769}{12150} + 8), Minimum (\frac{19 + 1621}{90}, \frac{- 42769 - 1621 1621}{12150} + 8)

e x t re m e f (x) = x^{3} - 2

e x t re m e 2 x^{2} + 12 x - 2

e x t re m e f (x) = - 5 x^{2} + 4 x - 6

e x t re m e P (q, s) = q + 6 + s

e x t re m e f (x) = 3 x + \frac{48}{x}