extreme f(x)=-100x^2+1800x

Lösung

extrempunkte

f (x) = - 100 x^{2} + 1800 x

Maximum (9, 8100)

Schritte zur Lösung

f^{'} (x) = - 200 x + 1800

Intervalle finden:

Ansteigend

: - \infty < x < 9,

Absteigend

: 9 < x < \infty

Stecke

x = 9

- 100 x^{2} + 1800 x : 8100

Maximum (9, 8100)

e x t re m e f (x) = \frac{1}{3} x^{3} - 2 x^{2} + 3 x - 4 [- 2.5]

e x t re m e f (x, y) = 3 x^{3} - (y + 1)^{3} - 9 x y + 3 y + 1

e x t re m e f (x) = \frac{x ^{4}}{4} - x^{3} + 3

e x t re m e f (x) = - 3 (x + 2) e^{4 x}, (- 5, 0)

e x t re m e f (x) = \frac{x ^{4} - 4 x ^{3}}{2}