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Beliebt Funktionen >

extreme 1/((x+1)(x+2)(x+3))

Lösung

extrempunkte

\frac{1}{( x + 1 ) ( x + 2 ) ( x + 3 )}

Lösung

Minimum (- \frac{6 + 3}{3}, \frac{3 3}{2}), Maximum (\frac{- 6 + 3}{3}, - \frac{3 3}{2})

Schritte zur Lösung

f^{'} (x) = - \frac{3 x ^{2} + 12 x + 11}{( x + 1 ) ^{2} ( x + 2 ) ^{2} ( x + 3 ) ^{2}}

Intervalle finden:

Absteigend

: - \infty < x < - 3,

Absteigend

: - 3 < x < - \frac{6 + 3}{3},

Ansteigend

: - \frac{6 + 3}{3} < x < - 2,

Ansteigend

: - 2 < x < \frac{3 - 6}{3},

Absteigend

: \frac{3 - 6}{3} < x < - 1,

Absteigend

: - 1 < x < \infty

Stecke

x = - \frac{6 + 3}{3}

in

\frac{1}{( x + 1 ) ( x + 2 ) ( x + 3 )} : \frac{3 3}{2}

Minimum (- \frac{6 + 3}{3}, \frac{3 3}{2})

Stecke

x = \frac{- 6 + 3}{3}

in

\frac{1}{( x + 1 ) ( x + 2 ) ( x + 3 )} : - \frac{3 3}{2}

Maximum (\frac{- 6 + 3}{3}, - \frac{3 3}{2})

Minimum (- \frac{6 + 3}{3}, \frac{3 3}{2}), Maximum (\frac{- 6 + 3}{3}, - \frac{3 3}{2})

Graph

Beliebte Beispiele

extreme f(x)=3x^2+10x-5

e x t re m e f (x) = 3 x^{2} + 10 x - 5

extreme f(x,y)=-x^2-4x-y^2+2y-1

e x t re m e f (x, y) = - x^{2} - 4 x - y^{2} + 2 y - 1

extreme y=xsqrt(x^2+1)

e x t re m e y = x x^{2} + 1

extreme f(x)=ln(4x)

e x t re m e f (x) = ln (4 x)

extreme x^3-y^3-2xy+6

e x t re m e x^{3} - y^{3} - 2 x y + 6