extreme f(x)=4.5x^2-7.1x+3.9

Lösung

extrempunkte

f (x) = 4.5 x^{2} - 7.1 x + 3.9

Minimum (0.78888 \dots, 1.09944 \dots)

Schritte zur Lösung

f^{'} (x) = 9 x - 7.1

Intervalle finden:

Absteigend

: - \infty < x < 0.78888 \dots,

Ansteigend

: 0.78888 \dots < x < \infty

Stecke

x = 0.78888 \dots

4.5 x^{2} - 7.1 x + 3.9 : 1.09944 \dots

Minimum (0.78888 \dots, 1.09944 \dots)

e x t re m e x^{3} - 9 x^{2} + 24 x - 12

e x t re m e 9 - x^{2}, - 3 \leq x \leq 2

e x t re m e f (x) = \frac{x ^{6}}{10} - \frac{2 x ^{5}}{3}

e x t re m e f (x, y) = 2 x^{2} + 4 y x - x - 2 y

e x t re m e f (x, y) = x^{2} y + 2 x y - 2 x y^{2} + 2