extreme-x^3+x^2+8x+8

Lösung

extrempunkte

- x^{3} + x^{2} + 8 x + 8

Minimum (- \frac{4}{3}, \frac{40}{27}), Maximum (2, 20)

Schritte zur Lösung

f^{'} (x) = - 3 x^{2} + 2 x + 8

Intervalle finden:

Absteigend

: - \infty < x < - \frac{4}{3},

Ansteigend

: - \frac{4}{3} < x < 2,

Absteigend

: 2 < x < \infty

Stecke

x = - \frac{4}{3}

- x^{3} + x^{2} + 8 x + 8 : \frac{40}{27}

Minimum (- \frac{4}{3}, \frac{40}{27})

Stecke

x = 2

- x^{3} + x^{2} + 8 x + 8 : 20

Maximum (2, 20)

Minimum (- \frac{4}{3}, \frac{40}{27}), Maximum (2, 20)

e x t re m e f (x) = - 3 x^{3} + 27 x

e x t re m e F (X, Y) = 3 X + 2 X^{2} + 4 Y + Y^{2} - 2 X Y

e x t re m e f (x) = 8 x^{2} - 6 x^{4}

e x t re m e T (x, y) = 27 - 8 x^{2} - 9 y^{2}

e x t re m e f (x, y) = x^{3} + y^{2} + x y + y