extreme 330x^2-1320x^3

Lösung

extrempunkte

330 x^{2} - 1320 x^{3}

Minimum (0, 0), Maximum (\frac{1}{6}, \frac{55}{18})

Schritte zur Lösung

f^{'} (x) = 660 x - 3960 x^{2}

Intervalle finden:

Absteigend

: - \infty < x < 0,

Ansteigend

: 0 < x < \frac{1}{6},

Absteigend

: \frac{1}{6} < x < \infty

Stecke

x = 0

330 x^{2} - 1320 x^{3} : 0

Minimum (0, 0)

Stecke

x = \frac{1}{6}

330 x^{2} - 1320 x^{3} : \frac{55}{18}

Maximum (\frac{1}{6}, \frac{55}{18})

Minimum (0, 0), Maximum (\frac{1}{6}, \frac{55}{18})

e x t re m e f (x) = \frac{∣ x - 3 ∣}{x ^{2} - 9}

e x t re m e y = x^{4} ln (\frac{x}{10})

e x t re m e f (x) = \frac{18}{( x ^{2} - 9 )}

e x t re m e f (x) = x^{3} - x^{2} - x + 7, - 1 \leq x \leq 2

e x t re m e g (t) = 8 t - t^{4}