extreme f(x)=-x^2+229x

Lösung

extrempunkte

f (x) = - x^{2} + 229 x

Maximum (\frac{229}{2}, \frac{52441}{4})

Schritte zur Lösung

f^{'} (x) = - 2 x + 229

Intervalle finden:

Ansteigend

: - \infty < x < \frac{229}{2},

Absteigend

: \frac{229}{2} < x < \infty

Stecke

x = \frac{229}{2}

- x^{2} + 229 x : \frac{52441}{4}

Maximum (\frac{229}{2}, \frac{52441}{4})

e x t re m e f (x) = 6 x - 0.2 x^{2}, 0 \leq x \leq 30

e x t re m e 5 x^{5} - 3 x^{4} + 2

e x t re m e f (x) = 4 - x, - 3 \leq x \leq 3

e x t re m e f (x, y) = (x^{2} - 9)^{2} + (y^{2} - 36)^{2}

e x t re m e f (x) = - 3 x^{2} - 12 x + 24 y^{2} + 12 y = 0