extreme x^3-x^2-x+7

Lösung

extrempunkte

x^{3} - x^{2} - x + 7

Maximum (- \frac{1}{3}, \frac{194}{27}), Minimum (1, 6)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} - 2 x - 1

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{1}{3},

Absteigend

: - \frac{1}{3} < x < 1,

Ansteigend

: 1 < x < \infty

Stecke

x = - \frac{1}{3}

x^{3} - x^{2} - x + 7 : \frac{194}{27}

Maximum (- \frac{1}{3}, \frac{194}{27})

Stecke

x = 1

x^{3} - x^{2} - x + 7 : 6

Minimum (1, 6)

Maximum (- \frac{1}{3}, \frac{194}{27}), Minimum (1, 6)

e x t re m e f (x) = x^{5} y^{2} - 3 x^{3} + 10 + 5 y^{3} - x y

e x t re m e f (x) = \frac{0.2 t}{t ^{2} + 59}

e x t re m e \frac{18}{x} + 3 x^{2}

e x t re m e f (x) = 3 x^{2} - 4 x + 12

e x t re m e f (x) = x (- \frac{2 x}{3} + 4)