en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Functions >

range of f(x)=(2x^2-3)/5

Solution

range

f (x) = \frac{2 x ^{2} - 3}{5}

Solution

f (x) \geq - \frac{3}{5}

+1

Interval Notation

[- \frac{3}{5}, \infty)

Solution steps

Vertex of

\frac{2 x ^{2} - 3}{5} :

Minimum

(0, - \frac{3}{5})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = \frac{2}{5},

Vertex

(x_{v}, y_{v}) = (0, - \frac{3}{5})

f (x) \geq - \frac{3}{5}

Graph

Popular Examples

critical e^{1/x}

extreme x^3-12x^2+36x+1

inverse of f(x)=x^2-12x+36

inverse of f(x)=8x^3-5

Frequently Asked Questions (FAQ)

What is the range of f(x)=(2x^2-3)/5 ?
The range of f(x)=(2x^2-3)/5 is f(x)>=-3/5