What is the domain of (65)/((1-8x)^2) ?

The domain of (65)/((1-8x)^2) is x 1/8

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domain of (65)/((1-8x)^2)

domain

\frac{65}{( 1 - 8 x ) ^{2}}

x < \frac{1}{8} or x > \frac{1}{8}

Interval Notation

(- \infty, \frac{1}{8}) \cup (\frac{1}{8}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{8}

The function domain

x < \frac{1}{8} or x > \frac{1}{8}

What is the domain of (65)/((1-8x)^2) ?
The domain of (65)/((1-8x)^2) is x< 1/8 \lor x> 1/8