What is the inverse of f(x)=4-6x^2,x<0 ?

The inverse of f(x)=4-6x^2,x<0 is sqrt(-(x-4)/6),-sqrt(-(x-4)/6)

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inverse of f(x)=4-6x^2,x<0

inverse

f (x) = 4 - 6 x^{2}, x < 0

- \frac{x - 4}{6}, - - \frac{x - 4}{6}

Solution steps

y = 4 - 6 x^{2}

Replace

x

with

y

x = 4 - 6 y^{2}

Solve for

y, x = 4 - 6 y^{2}

- \frac{x - 4}{6}, - - \frac{x - 4}{6}

What is the inverse of f(x)=4-6x^2,x<0 ?
The inverse of f(x)=4-6x^2,x<0 is sqrt(-(x-4)/6),-sqrt(-(x-4)/6)