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inverse of f(x)= 1/((x+9))domain of f(x)= 1/(x+15)midpoint (7,-2),(-5,-2)inverse of f(x)=x^3-5domain of f(x)=((2x^3-5))/(x^2+x-6)
Frequently Asked Questions (FAQ)
What is the symmetry y=x^2+6x+4 ?
The symmetry y=x^2+6x+4 is x=-3