What is the domain of f(x)=(4x^2-1)/(2x-1) ?

The domain of f(x)=(4x^2-1)/(2x-1) is x 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of f(x)=(4x^2-1)/(2x-1)

domain

f (x) = \frac{4 x ^{2} - 1}{2 x - 1}

x < \frac{1}{2} or x > \frac{1}{2}

Interval Notation

(- \infty, \frac{1}{2}) \cup (\frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{2}

The function domain

x < \frac{1}{2} or x > \frac{1}{2}

What is the domain of f(x)=(4x^2-1)/(2x-1) ?
The domain of f(x)=(4x^2-1)/(2x-1) is x< 1/2 \lor x> 1/2