What is the inverse of f(x)= 1/2 (x+3)^2-2 ?

The inverse of f(x)= 1/2 (x+3)^2-2 is sqrt(2x+4)-3,-sqrt(2x+4)-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)= 1/2 (x+3)^2-2

inverse

f (x) = \frac{1}{2} (x + 3)^{2} - 2

2 x + 4 - 3, - 2 x + 4 - 3

Solution steps

y = \frac{1}{2} (x + 3)^{2} - 2

Replace

x

with

y

x = \frac{1}{2} (y + 3)^{2} - 2

Solve for

y, x = \frac{1}{2} (y + 3)^{2} - 2

2 x + 4 - 3, - 2 x + 4 - 3

What is the inverse of f(x)= 1/2 (x+3)^2-2 ?
The inverse of f(x)= 1/2 (x+3)^2-2 is sqrt(2x+4)-3,-sqrt(2x+4)-3