extreme f(x)=(-7)/(x^2-9)

Lösung

extrempunkte

f (x) = \frac{- 7}{x ^{2} - 9}

Minimum (0, \frac{7}{9})

Schritte zur Lösung

f^{'} (x) = \frac{14 x}{( x ^{2} - 9 ) ^{2}}

Intervalle finden:

Absteigend

: - \infty < x < - 3,

Absteigend

: - 3 < x < 0,

Ansteigend

: 0 < x < 3,

Ansteigend

: 3 < x < \infty

Stecke

x = 0

\frac{- 7}{x ^{2} - 9} : \frac{7}{9}

Minimum (0, \frac{7}{9})

e x t re m e f (x, y) = 2 x^{2} + 3 y^{2} - 4 x - 3 y - 10

e x t re m e f (x, y) = e^{y} - y e^{x}

e x t re m e f (x) = 2 x + cos (2 x), 0 < x < π

e x t re m e f (x, y) = x^{2} - 3 x y + 5 x - 2 y + 6 y^{2} + 8

e x t re m e f (x) = \frac{3}{4} x^{4} - 3 x^{3} - 81 x^{2} - 16