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Beliebt Funktionen >

extreme f(x)=6x^4-32x^3+48x^2-7

Lösung

extrempunkte

f (x) = 6 x^{4} - 32 x^{3} + 48 x^{2} - 7

Lösung

Minimum (0, - 7), Sattel (2, 25)

Schritte zur Lösung

f^{'} (x) = 24 x^{3} - 96 x^{2} + 96 x

Intervalle finden:

Absteigend

: - \infty < x < 0,

Ansteigend

: 0 < x < 2,

Ansteigend

: 2 < x < \infty

Stecke

x = 0

in

6 x^{4} - 32 x^{3} + 48 x^{2} - 7 : - 7

Minimum (0, - 7)

Stecke

x = 2

in

6 x^{4} - 32 x^{3} + 48 x^{2} - 7 : 25

Sattel (2, 25)

Minimum (0, - 7), Sattel (2, 25)

Graph

Beliebte Beispiele

extreme f(x,y)=x^3+y^2-6x^2+y-1

e x t re m e f (x, y) = x^{3} + y^{2} - 6 x^{2} + y - 1

extreme y=x^3-3x^2+1

e x t re m e y = x^{3} - 3 x^{2} + 1

extreme f(x,y)=x^3+y^3-33xy

e x t re m e f (x, y) = x^{3} + y^{3} - 33 x y

extreme f(x)=-2x^2-16x-39

e x t re m e f (x) = - 2 x^{2} - 16 x - 39

extreme f(x)=((ln(x))^2)/x

e x t re m e f (x) = \frac{( ln ( x ) ) ^{2}}{x}