4x^2-5y=7

Lösung

4 x^{2} - 5 y = 7

(h, k) = (0, - \frac{7}{5}), p = \frac{5}{16}

Schritte zur Lösung

4 x^{2} - 5 y = 7

Rewrite

4 x^{2} - 5 y = 7

in the standard form:

4 \cdot \frac{5}{16} (y - (- \frac{7}{5})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{7}{5}), p = \frac{5}{16}

4 y^{2} - 5 x - 12 = 0

3 x^{2} + y = 5

a = \frac{2 x}{t ^{2}}

y^{(2)} - 10 y - 5 x + 15 = 0

x^{2} + y = - 1