What is 3x^2+3y^2-30x-36y-9=0 ?

The solution to 3x^2+3y^2-30x-36y-9=0 is Circle with (a,b)=(5,6),r=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

3x^2+3y^2-30x-36y-9=0

3 x^{2} + 3 y^{2} - 30 x - 36 y - 9 = 0

(a, b) = (5, 6), r = 8

Solution steps

3 x^{2} + 3 y^{2} - 30 x - 36 y - 9 = 0

Rewrite

3 x^{2} + 3 y^{2} - 30 x - 36 y - 9 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - 6)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (5, 6), r = 8

x^{2} + y^{2} - 8 x + 10 y = 128

(x - 3)^{2} + (y + 4)^{2} = 36

8 x + 32 y + y^{2} = - 263 - x^{2}

2 x^{2} + 2 y^{2} - 8 x + 28 y + 86 = 0

(x + 12)^{2} + (Y (x) - 4)^{2} - 30 = 0

What is 3x^2+3y^2-30x-36y-9=0 ?
The solution to 3x^2+3y^2-30x-36y-9=0 is Circle with (a,b)=(5,6),r=8