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Beliebt Geometry >

x^2+y^2+3y+7/4 =0

Lösung

x^{2} + y^{2} + 3 y + \frac{7}{4} = 0

Lösung

(a, b) = (0, - \frac{3}{2}), r = \frac{1}{2}

Schritte zur Lösung

x^{2} + y^{2} + 3 y + \frac{7}{4} = 0

Rewrite

x^{2} + y^{2} + 3 y + \frac{7}{4} = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - (- \frac{3}{2}))^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, - \frac{3}{2}), r = \frac{1}{2}

Graph

Beliebte Beispiele

x^2+(y-1)^2<= 1

x^{2} + (y - 1)^{2} \leq 1

(x+1)^2+(y+3)^2=7.9^2

(x + 1)^{2} + (y + 3)^{2} = 7. 9^{2}

a^2-2a+b^2-2b>= 0

a^{2} - 2 a + b^{2} - 2 b \geq 0

(x+3)^2+(y-1)^2=121

(x + 3)^{2} + (y - 1)^{2} = 121

(x-2)^2+(y-1)^2=8

(x - 2)^{2} + (y - 1)^{2} = 8