y^2+2y+12x+25=0

Lösung

y^{2} + 2 y + 12 x + 25 = 0

(h, k) = (- 2, - 1), p = - 3

Schritte zur Lösung

y^{2} + 2 y + 12 x + 25 = 0

Rewrite

y^{2} + 2 y + 12 x + 25 = 0

in the standard form

4 (- 3) (x - (- 2)) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 1), p = - 3

y^{2} = x + 81

3 x^{2} + 3 y = 0

y^{2} - 6 x = - 14 y - 49

y^{2} = x + 25

- f (x) = 4 x^{2} + 4 x - 2