5x+3y^2=0

Lösung

5 x + 3 y^{2} = 0

(h, k) = (0, 0), p = - \frac{5}{12}

Schritte zur Lösung

5 x + 3 y^{2} = 0

Rewrite

5 x + 3 y^{2} = 0

in the standard form:

4 (- \frac{5}{12}) (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{5}{12}

(y - 3)^{2} = 16 (x + 5)

y^{2} + 4 x + 1 = 0

x^{2} = y - 4

y = - 3 x^{2} - 12 x + 7

(x - 3)^{2} = 8 (y - 2)