3x^2+5x-k(x)=0

Lösung

3 x^{2} + 5 x - k (x) = 0

(h, k) = (- \frac{5}{6}, - \frac{25}{12}), p = \frac{1}{12}

Schritte zur Lösung

3 x^{2} + 5 x - y = 0

Rewrite

3 x^{2} + 5 x - y = 0

in the standard form

4 \cdot \frac{1}{12} (y - (- \frac{25}{12})) = (x - (- \frac{5}{6}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{6}, - \frac{25}{12}), p = \frac{1}{12}

4 x^{2} = - y

x - y^{2} = 3

x - y^{2} = 5

12 y + x^{2} = 0

2 x^{2} - 4 x + y - 3 = 0