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Beliebt Geometry >

((x+1)^2}{16}+\frac{(y-2)^2)/9 =1

Lösung

\frac{( x + 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{9} = 1

Lösung

(h, k) = (- 1, 2), a = 4, b = 3

Schritte zur Lösung

\frac{( x + 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{9} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{4 ^{2}} + \frac{( y - 2 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 2), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 1, 2), a = 4, b = 3

Graph

Beliebte Beispiele

x^2+4y^2+4x+32y-64=0

x^{2} + 4 y^{2} + 4 x + 32 y - 64 = 0

((x-2)^2)/(10)+((y+1)^2)/(25)=1

\frac{( x - 2 ) ^{2}}{10} + \frac{( y + 1 ) ^{2}}{25} = 1

36x^2+16y^2+144x-160y-32=0

36 x^{2} + 16 y^{2} + 144 x - 160 y - 32 = 0

9x^2+49y^2-114x+490y+1360=0

9 x^{2} + 49 y^{2} - 114 x + 490 y + 1360 = 0

((x-2)^2}{25}+\frac{(v+3)^2)/9 =1

\frac{( x - 2 ) ^{2}}{25} + \frac{( v + 3 ) ^{2}}{9} = 1