exzentrizität 5x^2+7y^2=70

Lösung

exzentrizität

5 x^{2} + 7 y^{2} = 70

\frac{2}{7}

Dezimale

0.53452 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

5 x^{2} + 7 y^{2} = 70 :

Ellipse with center

(h, k) = (0, 0), a = 14, b = 10

= \frac{( 14 ) ^{2} - ( 10 ) ^{2}}{14}

\frac{( 14 ) ^{2} - ( 10 ) ^{2}}{14} = \frac{2}{7}

= \frac{2}{7}

ecce n t r i c i t y 5 x^{2} + 10 y^{2} = 50

ecce n t r i c i t y x^{2} + 4 y^{2} - 2 x - 16 y + 13 = 0

ecce n t r i c i t y \frac{( x - 1 ) ^{2}}{6} + \frac{( y - 3 ) ^{2}}{2} = 1

ecce n t r i c i t y \frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1

ecce n t r i c i t y \frac{x ^{2}}{8} + \frac{y ^{2}}{3} = 1