(x-8)^2-(y+6)^2=1

解答

(x - 8)^{2} - (y + 6)^{2} = 1

(h, k) = (8, - 6), a = 1, b = 1

求解步骤

(x - 8)^{2} - (y + 6)^{2} = 1

将

(x - 8)^{2} - (y + 6)^{2} = 1

改写为标准双曲线方程形式

\frac{( x - 8 ) ^{2}}{1 ^{2}} - \frac{( y - ( - 6 ) ) ^{2}}{1 ^{2}} = 1

因此双曲线的性质为:

(h, k) = (8, - 6), a = 1, b = 1

4 y^{2} - 2 x^{2} = 1

\frac{x ^{2}}{1} - \frac{y ^{2}}{9} = 1

\frac{( x - 6 ) ^{2}}{36} - \frac{( y + 1 ) ^{2}}{25} = 1

so l v e f or x, (x - 0.5)^{2} + (x + 0.5)^{2} = r (x)^{2}

25 x^{2} - 16 y^{2} = 1