x^2+y^2-8x^2+7=0

解答

x^{2} + y^{2} - 8 x^{2} + 7 = 0

(h, k) = (0, 0), a = 1, b = 7

求解步骤

x^{2} + y^{2} - 8 x^{2} + 7 = 0

将

x^{2} + y^{2} - 8 x^{2} + 7 = 0

改写为标准双曲线方程形式

\frac{( x - 0 ) ^{2}}{1 ^{2}} - \frac{( y - 0 ) ^{2}}{( 7 ) ^{2}} = 1

因此双曲线的性质为:

(h, k) = (0, 0), a = 1, b = 7

16 x^{2} - 4 y^{2} = 64

(24 - x^{2}) + (4 - y)^{2} = \frac{x ^{2} + ( y + 3 ) ^{2}}{2 3 ^{2}}

(y - 1)^{2} - (x - 2)^{2} = 1

4 x^{2} - 9 y^{2} + 8 x - 36 y = 0

(\frac{x ^{2}}{1} + \frac{y ^{2}}{1 - 16}) (1 - 16) = 1 (1 - 16)