(3x-3)^2-(2y-4)^2=43+9+16

解

(3 x - 3)^{2} - (2 y - 4)^{2} = 43 + 9 + 16

(h, k) = (1, 2), a = \frac{2 17}{3}, b = 17

解答ステップ

(3 x - 3)^{2} - (2 y - 4)^{2} = 43 + 9 + 16

(3 x - 3)^{2} - (2 y - 4)^{2} = 43 + 9 + 16

を標準的な双曲線のequationで書き換える

\frac{( x - 1 ) ^{2}}{( \frac{2 17}{3} ) ^{2}} - \frac{( y - 2 ) ^{2}}{( 17 ) ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (1, 2), a = \frac{2 17}{3}, b = 17