-9x^2+25y^2-54x-50y-281=0

解答

- 9 x^{2} + 25 y^{2} - 54 x - 50 y - 281 = 0

(h, k) = (- 3, 1), a = 3, b = 5

求解步骤

- 9 x^{2} + 25 y^{2} - 54 x - 50 y - 281 = 0

将

- 9 x^{2} + 25 y^{2} - 54 x - 50 y - 281 = 0

改写为标准双曲线方程形式

\frac{( y - 1 ) ^{2}}{3 ^{2}} - \frac{( x - ( - 3 ) ) ^{2}}{5 ^{2}} = 1

因此双曲线的性质为:

(h, k) = (- 3, 1), a = 3, b = 5

\frac{x ^{2}}{64} - \frac{y ^{2}}{- 39} = 1

x^{2} - y^{2} - 2 x - 2 y - 4 = 0

2 x^{2} - y^{2} = 12

100 x^{2} - 44 y^{2} + 275 = 0

10 y^{2} + 60 y - 160 x - 255 = 20 x^{2}