焦点 ((x-3)^2)/9-((y-2)^2)/(22)=1

解答

焦点

\frac{( x - 3 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{22} = 1

(3 + 31, 2), (3 - 31, 2)

求解步骤

(h + c, k), (h - c, k)

计算双曲线性质

\frac{( x - 3 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{22} = 1 :

左右开口双曲线，

(h, k) = (3, 2), a = 3, b = 22

(3 + c, 2), (3 - c, 2)

计算

c :

c = 3^{2} + 22^{2} : 31

(3 + 31, 2), (3 - 31, 2)