center 3x^2-3y^2-12x-6y+3=0

Lösung

center

3 x^{2} - 3 y^{2} - 12 x - 6 y + 3 = 0

(2, - 1)

Schritte zur Lösung

3 x^{2} - 3 y^{2} - 12 x - 6 y + 3 = 0

Rewrite

3 x^{2} - 3 y^{2} - 12 x - 6 y + 3 = 0

in the form of a standard hyperbola equation

\frac{( x - 2 ) ^{2}}{( 2 ) ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{( 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, - 1), a = 2, b = 2

And the center is:

(2, - 1)