4x+y^2-7=0

Lösung

4 x + y^{2} - 7 = 0

(h, k) = (\frac{7}{4}, 0), p = - 1

Schritte zur Lösung

4 x + y^{2} - 7 = 0

Rewrite

4 x + y^{2} - 7 = 0

in the standard form:

4 (- 1) (x - \frac{7}{4}) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (\frac{7}{4}, 0), p = - 1

4 x = 2 y^{2} - 4 y - 23

x = 10 y - 24 - y^{2}

(y - 2)^{2} = 3 (x - 2)

(x - 4)^{2} = 16 (y + 4)

y^{2} + y + 2 = 7 x