x^2+5y=2

Lösung

x^{2} + 5 y = 2

(h, k) = (0, \frac{2}{5}), p = - \frac{5}{4}

Schritte zur Lösung

x^{2} + 5 y = 2

Rewrite

x^{2} + 5 y = 2

in the standard form:

4 (- \frac{5}{4}) (y - \frac{2}{5}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{2}{5}), p = - \frac{5}{4}

y = x^{2} + 12 x + 37

y^{2} + 20 x + 10 y - 5 = 0

x = y^{2} - 8 y + 18

(x - 2)^{2} = - 53 y

10 y = - 5 x^{2} + 8